[Tutorial] Introduction to programming using C (VIII)

[wth]

Write a program that checks if one string is part of another (if it's a substring).
Write the same program without using any loop construct (for, while, etc...)

seriously ? guess I'm clueless there after 2s thinking lol

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[Acid_Snake]

seriously ? guess I'm clueless there after 2s thinking lol

2s thinking? your a god! I wouldn't have lasted half a second

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[wth]

indeed pretty pointless trying such impossible thing imho xD

[wololo]

indeed pretty pointless trying such impossible thing imho xD

You can do it recursively. Not impossible at all.

[wth]

ah right didn't think about that, was thinking we had to do it with bare instructions forgetting we can loop without loops lol
without recusivity too impossible though xD

[Acid_Snake]

lol forgot about recursivity, I don't use it as a replacement for loop constructs too much, mostly use it to refresh something (i.e. a file browser in which the user has changed directory)

[m0skit0]

All I see is too much talking and no code

[Acid_Snake]

All I see is too much talking and no code

here you go bruh, code:

Code: Select all

; multi-segment executable file template.

data segment
    ; add your data here!
    msj_pedirCadena DB "Introduzca una cadena:$"
    msj_resultado DB "La cadena resultante es:$"
    saltoLinea DB 10, 13, '$'
    cadenaL DB 23 DUP(?)
    cadenaR DB 41 DUP(?)

ends

stack segment
    dw   128  dup(0)
ends

code segment       
    
;en el registro DX se encuentra la dirección de la cadena a imprimir
Imprimir PROC
    push ax
    mov ah, 9
    int 21h
    pop ax
    ret
Imprimir ENDP

;en el registro DX se encuentra la dirección de la cadena donde se
;almacenará el resultado de la lectura por teclado
LeerCadena PROC
    push ax
    mov ah, 0ah
    int 21h
    pop ax
    ret
LeerCadena ENDP
              
              
SepararCaracteres PROC
    push ax
    push cx
    push si
    push di
    mov si, 2
    mov di, 0
    mov cl, cadenaL[1]
    mov ch, 0
    mov si, cx
    inc si
    cmp cx, 0
    je finSepararCaracteres
bSepararCaracteres:
    mov al, cadenaL[si]
    mov cadenaR[di], al
    inc di
    dec si
    loop bSepararCaracteres
finSepararCaracteres:
    mov cadenaR[di], '$'
    pop di
    pop si
    pop cx
    pop ax
    ret
SepararCaracteres ENDP


start:
; set segment registers:
    mov ax, data
    mov ds, ax
    mov es, ax

    ; add your code here
    lea dx, msj_pedirCadena
    call Imprimir
    lea dx, saltoLinea
    call Imprimir
    lea dx, cadenaL
    mov cadenaL[0], 21
    call LeerCadena
    lea dx, saltoLinea
    call Imprimir
    call SepararCaracteres
    lea dx, msj_resultado
    call Imprimir
    lea dx, saltoLinea
    call Imprimir
    lea dx, cadenaR
    call Imprimir

    
    ; wait for any key....    
    mov ah, 1
    int 21h
    
    mov ax, 4c00h ; exit to operating system.
    int 21h    
ends

end start ; set entry point and stop the assembler.